-4.9x^2+160x+3=0

Solution for -4.9x^2+160x+3=0 equation:

-4.9x^2+160x+3=0

a = -4.9; b = 160; c = +3;
Δ = b2-4ac
Δ = 1602-4·(-4.9)·3
Δ = 25658.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-\sqrt{25658.8}}{2*-4.9}=\frac{-160-\sqrt{25658.8}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+\sqrt{25658.8}}{2*-4.9}=\frac{-160+\sqrt{25658.8}}{-9.8}
$